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5x^2-7=60
We move all terms to the left:
5x^2-7-(60)=0
We add all the numbers together, and all the variables
5x^2-67=0
a = 5; b = 0; c = -67;
Δ = b2-4ac
Δ = 02-4·5·(-67)
Δ = 1340
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1340}=\sqrt{4*335}=\sqrt{4}*\sqrt{335}=2\sqrt{335}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{335}}{2*5}=\frac{0-2\sqrt{335}}{10} =-\frac{2\sqrt{335}}{10} =-\frac{\sqrt{335}}{5} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{335}}{2*5}=\frac{0+2\sqrt{335}}{10} =\frac{2\sqrt{335}}{10} =\frac{\sqrt{335}}{5} $
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